Create a Loop for this process

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DARLINGTON ETAJE
DARLINGTON ETAJE el 23 de Jun. de 2021
Comentada: Stephen23 el 24 de Jun. de 2021
I have a process which works fine. You can see the code below. I need to create a loop for the process. I need the loop to take in multiple number of c. c is usually a 3 by 3 matrix. L is usual a 1 by 12 matrix.
n=3;
c1=[12 40 13;10 11 70;80 9 1]; % C matrix for member 1
c2=[0 0 -1;0 1 0;1 0 0]; % C matrix for member 2
c3=[0 1 0;0 0 1;1 0 0]; % C matrix for member 3
L1=[13 14 15 16 17 18 1 2 3 4 5 6]; % for member 1
L2=[1 2 3 4 5 6 7 8 9 10 11 12]; % for member 2
L3=[19 20 21 22 23 24 7 8 9 10 11 12]; % for member 3
L=[L1;L2;L3];
T1=zeros(size(L1,1));
T2=zeros(size(L2,1));
T3=zeros(size(L3,1));
for i=1:n
for j=1:n
T1(i,j)=c1(i,j);
T1(i+3,j+3)=c1(i,j);
T1(i+6,j+6)=c1(i,j);
T1(i+9,j+9)=c1(i,j);
T2(i,j)=c2(i,j);
T2(i+3,j+3)=c2(i,j);
T2(i+6,j+6)=c2(i,j);
T2(i+9,j+9)=c2(i,j);
T3(i,j)=c3(i,j);
T3(i+3,j+3)=c3(i,j);
T3(i+6,j+6)=c3(i,j);
T3(i+9,j+9)=c3(i,j);
end
end
  5 comentarios
DARLINGTON ETAJE
DARLINGTON ETAJE el 24 de Jun. de 2021
Thank you so much DGM. this is absolutely correct. I am looking for how to accept your answer...
I am grateful.
The only thing left is to find a way to create variabe names to assign each 12 by 12 matrices so I dont have 3D variables....is that even possible?
Stephen23
Stephen23 el 24 de Jun. de 2021
"The only thing left is to find a way to create variabe names to assign each 12 by 12 matrices so I dont have 3D variables....is that even possible?"
Of course it is possible, if you want to force yourself into writing slow, complex, inefficient code that is difficult to debug:
The neat, simple, very efficient approach is to use indexing, just as DGM has already correctly advised you.

Iniciar sesión para comentar.

Respuestas (1)

DGM
DGM el 24 de Jun. de 2021
Generally, using a bunch of numbered variables is something you should try to avoid.
That said, you can make the above code into a function that will return a variable length list of T arrays for an equal-length list of C arrays.
C1 = rand(3,3);
C2 = rand(3,3);
dn = 4;
% output list length should be same as number of Cn arrays
[T1 T2] = makebdiag(dn,C1,C2)
function varargout = makebdiag(dn,varargin)
varargout = cell(size(varargin));
for n = 1:numel(varargin)
arglist = repmat(varargin(n),[1 dn]);
varargout{n} = blkdiag(arglist{:});
end
end

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