Loop to populate a 12 by 12 matrix

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DARLINGTON ETAJE
DARLINGTON ETAJE el 24 de Jun. de 2021
Comentada: DARLINGTON ETAJE el 24 de Jun. de 2021
Hello Guys,
I am tryling to form a 12 by 12 matrix for 11 elements. I am getting some errors. Take a look at my code below: it looks perfect to me but it is not working
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1=zeros(12,1);
K2=zeros(12,1);
K3=zeros(12,1);
K4=zeros(12,1);
K5=zeros(12,1);
K6=zeros(12,1);
K7=zeros(12,1);
K8=zeros(12,1);
K9=zeros(12,1);
K10=zeros(12,1);
K11=zeros(12,1);
K12=zeros(12,1);
K=zeros(12,12);
for i=1:n
K1(i)=[SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2(i)=[0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3(i)=[0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4(i)=[0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5(i)=[0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6(i)=[0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7(i)=-K1;
K8(i)=-K2;
K9(i)=-K3;
K10(i)=-K4;
K11(i)=[0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12(i)=[0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K(i)=[K1(i) K2(i) K3(i) K4(i) K5(i) K6(i) K7(i) K8(i) K9(i) K10(i) K11(i) K12(i)];
end
  1 comentario
DARLINGTON ETAJE
DARLINGTON ETAJE el 24 de Jun. de 2021
Thank you so much Walter. It worked. You are an excellent person. The only challenge is that working with the code in struct is different than in a double.

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Respuesta aceptada

Walter Roberson
Walter Roberson el 24 de Jun. de 2021
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1 = repmat({zeros(12,1)},n,1);
K2 = repmat({zeros(12,1)},n,1);
K3 = repmat({zeros(12,1)},n,1);
K4 = repmat({zeros(12,1)},n,1);
K5 = repmat({zeros(12,1)},n,1);
K6 = repmat({zeros(12,1)},n,1);
K7 = repmat({zeros(12,1)},n,1);
K8 = repmat({zeros(12,1)},n,1);
K9 = repmat({zeros(12,1)},n,1);
K10 = repmat({zeros(12,1)},n,1);
K11 = repmat({zeros(12,1)},n,1);
K12 = repmat({zeros(12,1)},n,1);
K = repmat({zeros(12,1)},n,1);
for i=1:n
K1{i} = [SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2{i} = [0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3{i} = [0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4{i} = [0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5{i} = [0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6{i} = [0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7{i} = -K1{i};
K8{i} = -K2{i};
K9{i} = -K3{i};
K10{i} = -K4{i};
K11{i} = [0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12{i} = [0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K{i} = [K1(i); K2(i); K3(i); K4(i); K5(i); K6(i); K7(i); K8(i); K9(i); K10(i); K11(i); K12(i)];
end
K
K = 11×1 cell array
{12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell}
K{1}
ans = 12×1 cell array
{12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double}
K{1}{1}
ans = 12×1
0.3563 0 0 0 0 0 -0.3563 0 0 0

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