How can i vectorize this assignment to a structure array?

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Alfredo
Alfredo el 11 de Sept. de 2013
Hello everyone, I have initialized a structure array like this:
[v(1:5).s] = deal( false(1, 3) );
Now, I would like to modify only certain elements of it. And I can do it with a for loop, like this:
idv = [2 4 5]; % v indexes
ids = [1 1 3]; % corresponding s indexes where to write
for i=1:length(idv)
v( idv(i) ).s( ids(i) ) = true;
end
Is there a way to vectorize this operation?
If not, can I at least vectorize this one?
for i = 1:NoP
vm(i).s = false(size(vm(i).v));
end
Thank you very much!

Respuestas (2)

Jan
Jan el 12 de Sept. de 2013
Editada: Jan el 12 de Sept. de 2013
If idv is large and not unique, finding corresponding elements at first can increase the speed under some conditions. If idv is unique, the only way to improve the speed is to use a smarter structure for your data. The vectors idv and ids are a very compact and efficient way to store the positions of the enabled bits already. Inflating this structure by using a struct array with multiple fields, the performance must degrade and even a hyper-intelligent vectorization cannot lead to really fast code.
[EDITED] The 2nd loop ("for i = 1:NoP") cannot be vectorized also. And even if there would be a method, it could not be remarkably faster than the loop.
A vectorization is efficient, when the same procedure can be applied to an array of data instead of processing each element independently. Example:
a = [sin(1.1), sin(1.2)] % "Slow" elementwise operation
b = sin([1.1, 1.2]) % "Fast" vectorized code
But setting a field of a struct array to different values does not allow to combine any data to a continuous block.

Azzi Abdelmalek
Azzi Abdelmalek el 11 de Sept. de 2013
I think your for loop is the better way to do it. Are you trying to make your code faster?

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