An object with the biggest amount of scope in the Binary image

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Hello, I have a binary image with n white objects (not connected). How can I leave only the object with the biggest amount of scope in the picture I can do it by - bwareaopen, but in this way I have to know approximate size of an object. sorry for my english. thnx

Respuesta aceptada

Image Analyst
Image Analyst el 13 de Sept. de 2013
Try this:
grayImage = imread('coins.png');
subplot(2,2,1);
imshow(grayImage);
binaryImage = grayImage > 100;
binaryImage = imfill(binaryImage, 'holes'); % Fill holes.
[labeledImage, numObjects] = bwlabel(binaryImage);
stats = regionprops(labeledImage,'Area');
allAreas = [stats.Area]
[~, indexOfLargest] = max(allAreas);
largestBlob = ismember(labeledImage, indexOfLargest)>0;
subplot(2,2,2);
imshow(largestBlob);
title('Largest');
keeperIndexes = 1:numObjects;
keeperIndexes(indexOfLargest) = [];
binaryImage2 = ismember(labeledImage, keeperIndexes)>0;
subplot(2,2,3);
imshow(binaryImage2);
title('All Except Largest');

Más respuestas (2)

Adam Filion
Adam Filion el 12 de Sept. de 2013
Editada: Adam Filion el 12 de Sept. de 2013
If you have Image Processing Toolbox you can use the function regionprops. It comes out to something like this, where tm is the binary image.
cc = bwconncomp(tm);
stats = regionprops(cc,'Area');
A = [stats.Area];
[~,biggest] = max(A);
tm(labelmatrix(cc)~=biggest) = 0;
You can watch a recorded presentation that steps through a similar example here:
  2 comentarios
Felix
Felix el 12 de Sept. de 2013
Editada: Image Analyst el 13 de Sept. de 2013
Thanks for the help, it close enough to what I asked, however, it erased all the small arias except the closest ones to the object . can you tall me why is that? sorry i can't upload an image, can i send it to your e-mail?
Image Analyst
Image Analyst el 13 de Sept. de 2013
Editada: Image Analyst el 13 de Sept. de 2013
Try uploading an image to http://snag.gy or http://tinypic.com.

Iniciar sesión para comentar.


Sean de Wolski
Sean de Wolski el 17 de Sept. de 2013
Good timing, I just posted this function a few minutes ago!

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