Removing top and bottom outliers

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Nicholas Omoding
Nicholas Omoding el 12 de Jul. de 2021
Editada: Scott MacKenzie el 12 de Jul. de 2021
I’ve surface damage depth (D) for 3D points (x, y, z). I’d like remove top and bottom 5% of the D values with their corresponding (x, y, z) from the matrix so that I can plot the remaining 90% of the points. Based on the attached sub set of the data, please kindly assist on the based way to achieve this with the rmoutliers function?

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Scott MacKenzie
Scott MacKenzie el 12 de Jul. de 2021
Editada: Scott MacKenzie el 12 de Jul. de 2021
Yes, the rmoutliers function will do the trick. After removing the top and bottom 5% of the values, the vectors below are reduced from 100 elements each to 90 elements each.
% test data
x = rand(1,100);
y = rand(1,100);
z = rand(1,100);
D = rand(1,100);
[D, TF] = rmoutliers(D, 'percentiles', [5 95]);
x(TF) = [];
y(TF) = [];
z(TF) = [];
whos
Name Size Bytes Class Attributes D 1x90 720 double TF 1x100 100 logical x 1x90 720 double y 1x90 720 double z 1x90 720 double

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