how to do average over third dimension?

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Lilya
Lilya el 26 de Jul. de 2021
Comentada: Star Strider el 26 de Jul. de 2021
Hi all,
I have multiple 3D matrices with the dimension of 21*41*24 for each which 24 (third dimension) is 24 hours.
I wanted to calculate 6 hours average for the third dimension.
Where I am mistaken?
NHours=size(ucom,3);
NDays=NHours/6;
out = nanmean(permute(reshape(ucom,[6,NDays]),[2,1,3]),3);
  2 comentarios
KSSV
KSSV el 26 de Jul. de 2021
Read about mean there is option to get mean in any dimension.
Lilya
Lilya el 26 de Jul. de 2021
OK..Thank you :)

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Respuesta aceptada

Star Strider
Star Strider el 26 de Jul. de 2021
Taking a slightly shorter example, try something like this —
% ucom = randi(9,21,41,24);
ucom = randi(9, 3, 4, 24);
sz_ucom = size(ucom);
ucomr = reshape(ucom,sz_ucom(1),sz_ucom(2),[],6);
out = nanmean(ucomr,4)
out =
out(:,:,1) = 5.6667 5.5000 4.8333 3.1667 5.8333 4.5000 5.6667 4.0000 5.8333 5.1667 5.0000 4.5000 out(:,:,2) = 3.8333 6.0000 4.5000 6.0000 6.0000 5.1667 5.6667 2.5000 3.1667 6.0000 5.3333 5.3333 out(:,:,3) = 3.8333 3.6667 6.3333 5.3333 4.1667 6.0000 5.5000 5.6667 3.6667 5.0000 4.1667 6.3333 out(:,:,4) = 5.5000 5.5000 4.1667 2.6667 3.1667 3.6667 4.8333 4.8333 7.0000 3.8333 5.5000 6.3333
The ‘out’ variable now has 4 blocks of 6-hour averages
.
  8 comentarios
Lilya
Lilya el 26 de Jul. de 2021
It works!!
Much much appreciated.
Star Strider
Star Strider el 26 de Jul. de 2021
As always, my pleasure!
(Sorry for the delay — I was off doing other things.)
.

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