How do I join a single string with multiple strings?
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Tom Wright
el 17 de Oct. de 2013
Comentada: Tom Wright
el 17 de Oct. de 2013
Hi, I know I can do this with loops but there must be a nicer way.
basepath='/data/';
filebase='video_';
fileext='.avi';
files=['00a' '00b' '00c'];
I'd like the output to be the vector
['/data/video_00a.avi' '/data/video_00b.avi' '/data/video_00c.avi']
(although I'd also be happy with a vertical matrix.
Thanks Tom
1 comentario
Matt Kindig
el 17 de Oct. de 2013
Editada: Matt Kindig
el 17 de Oct. de 2013
Are you sure you don't want 'files' to be a cell array? Because the way you've defined files, it will just concatenate 00a, 00b, etc. as one string. Observe:
files=['00a' '00b' '00c']
% files = '00a00b00c'
This is probably less useful to you. Instead, define 'files' as:
files = {'00a', '00b', '00c'}
Respuesta aceptada
Azzi Abdelmalek
el 17 de Oct. de 2013
Editada: Azzi Abdelmalek
el 17 de Oct. de 2013
basepath='/data/';
filebase='video_';
fileext='.avi';
files={'00a', '00b', '00c'}
cellfun(@(x) sprintf([basepath filebase '%s' fileext],x),files,'un',0)
Look at
doc cell
Más respuestas (1)
Vivek Selvam
el 17 de Oct. de 2013
Here you go, Tom.
basepath = '/data/';
filebase = 'video_';
fileext = '.avi';
files = ['00a'; '00b'; '00c'];
n = size(files,1);
horzcat(repmat(basepath,n,1), repmat(filebase,n,1), files, repmat(fileext,n,1))
0 comentarios
Ver también
Categorías
Más información sobre Convert Image Type en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!