findding neares label

Hi I have the following 3 matrix. I =

     0     0     1     1     0     0
     0     1     0     0     1     0
     1     0     0     0     0     1
     0     0     0     0     0     0
     0     0     0     0     0     0
     0     0     0     0     0     0

I1 =

     0     0     0     0     0     0
     0     1     1     1     1     0
     1     0     0     0     0     1
     0     0     0     0     0     0
     0     0     0     0     0     0
     0     0     0     0     0     0

I2 =

     0     0     0     0     0     0
     0     0     0     0     0     0
     1     0     0     0     0     1
     0     1     0     0     1     0
     0     0     1     1     0     0
     0     0     0     0     0     0

I need to know the 1s in I1 is closer to the which matrices' 1s. Here If some one looks at the matrix then obviously 1s in I1 is closer to the 1s in I than in I2.

Is there any one to help?

Thanks

Answer 1

[Andrei Bobrov]

so

D = bwdist(I)
P1 = sum(D(logical(I1)))
P2 = sum(D(logical(I2)))
if P1 < P2 , disp('I1 is closer to the 1s in I than in I2');
else disp('I2 is closer to the 1s in I than in I1'); end

Answer 2

[Walter Roberson]

V = 1:size(I,1);
Ipos = V * I;
I1pos = V * I1;
I2pos = V * I2;
I1score = sum(abs(Ipos-I1pos));
I2score = sum(abs(Ipos-I2pos));
if I1score < I2score
  %I1
elseif I1score > I2score
  %I2
else
  %equal
end

This is based on my arbitrary meaning of "closer", as you are very vague as to what "closer" means.

[Mohammad Golam Kibria]

for I1 and I,pixel distance having 1 are 0,0,1,1,0,0 and for I1 and I2 are 0,2,root(3),root(3),2,0, so it may be consider that s in I1 is closer to the 1s in I than in I2.

perhaps now it is clear