This is a shamless answer,I admit...But the explicit recurrence relation is insanely slow,hope to see you guys solve this problem more efficient.
I prefer g(end+1:end+g(gptr))=gptr; to usage of repmat. My machine to solve 1234567 takes 48msec vs 15.4 sec using repmat. repmat has a performance issue with large column replication. Unfortunately score is code size and not time.
totally agree (not to mention the entire 'growing inside a loop' uglyness), cody style is very far from any reasonable coding standard...
That's very interesting. The time difference on my (presumably much older) version of MATLAB is much less. Your method gives me an average time of about 18.8 sec, while repmat gives me an average time of 19.5 sec.
May you give a short explanation on this solution?
This is the asymptotic expression of nth term based on the golden ratio. See http://en.wikipedia.org/wiki/Golomb_sequence
Return the 3n+1 sequence for n
Find the peak 3n+1 sequence value
Calculate the Number of Sign Changes in a Row Vector (No Element Is Zero)
S-T-R-E-T-C-H I-T O-U-T
Diophantine Equations (Inspired by Project Euler, problem 66)
Fun with a compass
High Precision Square Root (Inspired by Project Euler 80)
Highest powers in factorials
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