Using the following definition of the 666 function for this problem: f(n)=sin('nnn')-cos(n*n*n), write a function that returns the first N integer zeros of the 666 function, formatted as 'nnn'.
For example:
sixsixsix(1) = should return 666
sixsixsix(7) should return 666 151515 181818 272727 424242 636363 666666
Note 1: Consider a 'zero' to occur when f(n)<1e-8
Note 2: The sin and cosine functions must be in degrees, not radians.
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This problem wants us to find the first n integer roots of the 666 function. It took me a while to understand this problem. The first integer root is at sind(666)-cosd(6^3).
The notation 'nnn' is shorthand for "concatenate three copies of n". As I understand the problem, the roots of the function (i.e., the values of n at which the function is zero) are 6, 15, 18, 27, etc. However, we are to output 'nnn': 666, 151515, 181818, 272727, etc.