Problem 44676. Mean = Standard Deviation

Created by Mehmet OZC

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Last Solution submitted on Jul 30, 2020

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Mehmet OZC on 7 Jun 2018

zeros(x,1) is not an acceptable solution. A new assert line added and all solutions are rescored

James on 7 Jun 2018

I was wondering what the one line command was to do this when I saw the scores as low as they were!! Those were before the all(y>0) condition was added.

bainhome on 8 Jun 2018

haha! I was discussed this one with binbin yesterday, he said this one was ill-conditioned, sooner or later will be fixed. We submit a solution anyway, sort of for fun. hope you don't mind it. But if really do that can be tricky indeed. good problem.

Rafael S.T. Vieira on 30 Jul 2020 at 12:24

I don't agree, bainhome, since all non-negative means m can be represented by sets with k/2 zeros and k/2 2*m numbers for any even k, which would render an infinite number of "ill-conditioned" sets for all m. For mean and std 1: [0 2], [0 0 2 2], [0 0 0 2 2 2], [0 0 0 0 2 2 2 2], ... .For mean and std 2: [0 4], [0 0 4 4], [0 0 0 4 4 4], [0 0 0 0 4 4 4 4], ... And for mean and std 3: [0 6], [0 0 6 6], [0 0 0 6 6 6], [0 0 0 0 6 6 6 6], ... In fact , m=0 is just a particular case.

PS: This is not considered a solution for this problem currently since it doesn't allow using zeros.

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Problem 44676. Mean = Standard Deviation

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Problem 44676. Mean = Standard Deviation

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