- The positions of different chess pieces are given in a cell p .
- The position of the king is given as x
Determine if the opponent king is in check for individual scenerios.
- x='Kg7'
- p={'Qe5','Qg5','Qb5','Qa7'}
output= [1,1,0,1]
N.b.any invalid position should produce 0. u may imagine p as the white pieces and x as the black king for clarity.
Solution Stats
Problem Comments
5 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers11
Suggested Problems
-
Is my wife right? Now with even more wrong husband
1339 Solvers
-
Get an array of month-ends in a date range
116 Solvers
-
Generate a string like abbcccddddeeeee
274 Solvers
-
109 Solvers
-
Penny flipping - calculate winning probability (easy)
194 Solvers
More from this Author174
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Asif,
I really like this problem, but I don't understand why 'h6' has 'Kg7' in check in Problem 2, but 'e1' does not have 'Kf2' in check in Problem 6. Aren't these two situations the same?
William,
the opponent's pawn can never be in row-1. they can only move/check forward.
Asif,
Thanks, but my point is that the pawn is in row-1 in *both* cases, so they should both be in check or neither should be in check. Since you described 'x' as being the 'opponent King', I think that both should be in check.
william,
i might not have understood u totally.
what i meant to say is that -- there are some invalid position/moves. for example, the pawn can jump from a2 to a4 but not from a3 to a5-thats an invalid move. similarly a white pawn can never be at the location a1-- their position starts from a2-so placing a pawn in row-1 is an invalid move.
in test-6, the pawn in e1 could check the king - but its own position is invalid.it could not be in that position in the 1st place. thats why 0.
in test-2,3; the pawn is in h6. a pawn can be in the column-h or row-6.so thats a valid position.
https://en.wikipedia.org/wiki/Pawn_(chess)
Asif,
Aha! Tricky, and very clever. Thanks for posting this interesting problem!