A lot of solutions don't work with something like n=5 and m=0
Not at all...
For n-by-n matrix, m=1 if n is odd number.
ur problems are really interesting
This problem has some issues because some pairs (n,m) do not have a solution. For instance, it is impossible to find a matrix such that m = n^2 -1 since a rotation pivot does not move. Moreover, there are floor((n^2)/4) cycles of numbers, and when we match the cycle beginning with its end, it creates two matches. It is possible to do some manipulations to have an m greater than n^2 - floor((n^2)/4), but not always.
can you give an example of a matrix before and after?
My code fails for some of the cases I've mentioned. The current leading solution does better (finding some solutions my code can't), yet sometimes it enters into an infinite loop.
i had no idea this was gonna work :p
radius of a spherical planet
Project Euler: Problem 9, Pythagorean numbers
Numbers with prime factors 2, 3 and 5.
Find perfect placement of non-rotating dominoes (easier)
Find out missing number from a vector of 9 elements
Placing Beads Neatly in a Box
How Many Months Until It's Today Again?
Beads on a Necklace (Convex Hulls)
Make a function that returns its own character count
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