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종영


Last seen: 13 días hace |  Con actividad desde 2024

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planar array FFT DOA
clc; clear all; close all; f = 3e8; c = 3e8; lambda = c/f; dx = 0.5*lambda; N = 40; theta = [0]; d = lambda / 2; R...

3 meses hace | 1 respuesta | 0

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MLS(moving least squares) algorithm problem... help me!!!
During MLS, it was conducted as follows. I'm curious about this, I designated weighting for five adjacent points for one point, ...

3 meses hace | 1 respuesta | 0

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plomb ifft sequence??? please help me!!!!
Plomb was conducted, but modification was not performed to fill the gap here. After that, if you do an ift, the position of ...

4 meses hace | 2 respuestas | 0

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Working in Excel with live on MATLAB
On matlab, I am going to import an Excel file and work on it live in real time. If I change the value in Excel, I want to ref...

6 meses hace | 2 respuestas | 0

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how to get inverse ?
a = [1 2 3]; b = [3 2 1 ].'; c = a*b; aa = c*pinv(b) ; i want to answer a = aa but i can't pleas~~~~

6 meses hace | 1 respuesta | 0

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Separate graph arrows for two y-axes on the matlab
In the figure below, the circle arrows are used for two y-axes to indicate which axis the graph follows, how do you do this? ...

8 meses hace | 2 respuestas | 0

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Distributed digital subarray analysis
clc; clear all; close all; f = 3e8; Nx = 10; % number of antennas in subarray Ns1 = 5;% number of sub array h = 8; % n...

9 meses hace | 1 respuesta | 0

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in DOA, ifft weighting vector
clc; clear all; close all %% array parameters c = 3e8; f = 3e8; % nominal frequency for array antenna interval setting lam...

11 meses hace | 1 respuesta | 0

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Comparing Weight Values with LSM and ifft
clc; clear all; close all %% array parameters c = 3e8; f = 3e8; % nominal frequency for array antenna interval setting lam...

11 meses hace | 1 respuesta | 0

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chebyshev Beam size control
function Chebyshev_real = Chebyshev_real(N,ste) R_dB=30; R=10^(R_dB/20); N=10; m=N-1; x0=cosh((1/m)*acosh(R)); u=sind(-...

11 meses hace | 1 respuesta | 0

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In ULA monopulse, i can't find sum beam and difference beam
clc; clear all; close all; % Transmitted signal f = 3e8; %[Hz] c = 3e8; lambda = c/f; N = 10; %number of element ...

11 meses hace | 1 respuesta | 0

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