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Neel Singh


Con actividad desde 2015

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My code primarily depends on the diameter or "d" as it is defined, however changing it to a smaller value beyond 0.001, all the results just go to infinity. How do i get around the rounding issue (it seems) ?
clear all clc rho = 2000; Cd = 0.44; %d = input('input diameter'); d = 0.01; %d = 9.99*10^-4; A = (d/2)^2*pi; %m = input...

más de 9 años hace | 2 respuestas | 0

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