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Andrew Wiebe


Con actividad desde 2015

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Estadística

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Find intersection of two matrices of data.
I have 2 matrices of data, each two dimensions, and I want to find the points at which the lines from these matrices would inter...

casi 9 años hace | 1 respuesta | 0

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Find a point of intersection of two 2D matrices.
How would i find the point of intersection of two 2D data matrices. Neither originate from equations of lines. i want the (x,y) ...

casi 9 años hace | 0 respuestas | 0

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Figure with multiple views
I have a surface generated in a graph on Matlab. I am curious about how i can make a single figure which contains multiple views...

casi 9 años hace | 1 respuesta | 0

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Interpolating between lines in 3D
I have a 42x100x3 matrix, where 1,2,3 represent the x,y,z values, each row represents one of the 42 lines. I have a mesh grid of...

alrededor de 9 años hace | 0 respuestas | 0

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Interpolating between lines in 3D
I have a number of 3D lines in space, and i want to interpolate between the each line to get a surface from the lines. What woul...

alrededor de 9 años hace | 1 respuesta | 0

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Error using interpolation line 64
How do i get around this error with says: Error using interp (line 64) Length of data sequence must be at least 9. You eithe...

alrededor de 9 años hace | 1 respuesta | 0

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Converting a matrix into an array
How would i convert a matrix into an array, where each column of numbers turns into a single element(matrix)? so all I'm left wi...

alrededor de 9 años hace | 1 respuesta | 0

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Judging input word based on first letter
How would I write an m-file that asks a user to input a word and only returns a correct response if the word begins with "A","B"...

alrededor de 9 años hace | 1 respuesta | 0

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Using a matrix where every column has a different number of rows, to obtain a matrix with the exact same dimensions for every column.
for n=1:42; Lx(max(size(L(1:end,n))))=L(1:end,n).*[sind(theta{n,1}(1:end,1))]; end. L is a matrix with 42 columns...

alrededor de 9 años hace | 1 respuesta | 0

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Nested for loops help!
Ok i think it worked, just confused because it lists the name of each element within n as the values, and i expected them to be ...

alrededor de 9 años hace | 0

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Nested for loops help!
If i have m1(n,1)=(m2(n,1)+((m3(n,1))*p)); Where m1 m2 and m3 are all arrays. if i wanted the range of n=1:42, ...

alrededor de 9 años hace | 2 respuestas | 0

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If I have a 4x4 cell array, 'm' where each element is a matrix expressed as '4x4 double', what would be the notation to access the values of a matrix within 'm'.
say m = 4x4 double 4x4 double 4x4 double 4x4 double 4x4 double 4x4 double 4x4 double 4x4 double 4x...

alrededor de 9 años hace | 2 respuestas | 0

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How do i do a for loop within a for loop with a variable changing n=1:42.
If i wanted to create a for loop where n=1:42, but there is another variable, l whose dimension is dependant on the variable n. ...

alrededor de 9 años hace | 1 respuesta | 0

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If I have a 4x4 cell array, 'm' where each element is a matrix expressed as '4x4 double', what would be the notation to access the values of a matrix within 'm'.
Wonderful! one other thing, I'm trying to set two separate variables in a for loop to be a range of numbers i.e. n=1:42 l=1:53. ...

alrededor de 9 años hace | 0

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I have this code and when run it's telling me that the index exceeds the matrix dimensions. Im in the process of teaching myself matlab. Can anyone help please?
for n=1:42; for n=1; l=1:52; for n=[2 3 4 5 6 9]; l=1:16; for n=[7:8,10:41]; ...

alrededor de 9 años hace | 0 respuestas | 0

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