Multiplying 2 matrices, using a for loop and storing results in a table.
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Anders
el 26 de Oct. de 2013
Comentada: Anders
el 28 de Oct. de 2013
Hey.
I have to multiply D=[cos(pi/18) -sin(pi/18); sin(pi/18) cos(pi/18)] by X= [0.80;0] 9 times, using a for loop. I want to store the results in a table of the form: X=zeros(2,10).
I've tried to do it like this:
X=[0.80;0]
t=pi/18
D=[cos(t) -sin(t); sin(t) cos(t)]
d=D*X
X=zeros(2,10)
for D=10:2,
X(D)=d;
end
But this just writes:
X =
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
Anders. I'm a bit lost.
3 comentarios
Respuesta aceptada
Andrei Bobrov
el 26 de Oct. de 2013
Editada: Andrei Bobrov
el 27 de Oct. de 2013
[EDIT]
X=[0.80;0];
t=pi/18;
D=[cos(t) -sin(t); sin(t) cos(t)];
X(2,10) = 0;
for jj = 2:size(X,2)
X(:,jj) = D*X(:,jj-1);
end
4 comentarios
Más respuestas (1)
sixwwwwww
el 27 de Oct. de 2013
Dear Andres, you can do it as follows using for loop:
D = [cos(pi/18) -sin(pi/18); sin(pi/18) cos(pi/18)];
X = [0.80;0];
result = zeros(2, 9);
for i = 1:9
result(1, i) = D(1, 1) * X(1) + D(1, 2) * X(2);
result(2, i) = D(2, 1) * X(1) + D(2, 2) * X(2);
end
disp(result)
I hope it helps. Good luck!
Ver también
Categorías
Más información sobre Multidimensional Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!