what am I doing wrong?

I have a doubt in the representation of a discrete signal. With help from Azzi Abdelmalek I wrote the following code

p=-5:0.0001:5;
%Input number
Imp=input('number pulse:\n');
out=zeros(1,numel(p));
for x = 1:Imp

      %input amplification
      a(x)=input('amplification pulse:\n');
      %step position  
      p(x)=input('initial Position:\n');  

      out=out+a(x)*heaviside(p-p(x));
      stem(p,out);
  end

xlabel('Position');
ylabel('Amplification');
title('graph');
grid on;

but the representation is wrong,what am I doing wrong?

The signal must be a sum of impulses and the user to choose the number of pulses and each pulse amplitude and choose your position, as follows: x (n) = a1  (n-n1) a2 +  (n-n2) + ...

Answer 1

[Walter Roberson]

You are using p to represent the locations being sampled at, and you are using p(x) to represent the pulse positions, but p(x) is the same vector as vector p . You should be using two different names for the two different items.

[Manuel]

the problem is the same

[Image Analyst]

Please update your code with the variables that have the new names that Walter suggested. You said you made the changes he suggested, but we don't want to make recommendations on code we haven't seen.

[Manuel]

if true
p=-5:0.0001:5;
%Input number
Imp=input('number pulse:\n');
out=zeros(1,numel(p));
for x = 1:Imp
    %input amplification
    a(x)=input('amplification pulse:\n');
    %step position  
    p1(x)=input('initial Position:\n');  
    out=out+a(x)*heaviside(p-p1(x));
    stem(p,out);
end
xlabel('Position');
ylabel('Amplification');
title('graph');
grid on;
end

Answer 2

[Manuel]

I do not understand what I'm doing wrong