spatial coordinates of BW image

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MANI MANI
MANI MANI el 6 de Nov. de 2013
Editada: Jan el 6 de Nov. de 2013
I have a BW image in which few pixels are white rest all are black.. I want to store the spatial co-ordinates of only white pixels in to 2D matrix having only 2 columns(to represent x y coordinates) and any number of rows.. How do I do that? Pl. help me.

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Image Analyst
Image Analyst el 6 de Nov. de 2013
I don't know why that would be necessary, but if you insist:
[rows, columns] = find(BW); % 2 1-D vectors.
xy = [columns, rows]; % Stitch together to form N by 2 (x,y) array.
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MANI MANI
MANI MANI el 6 de Nov. de 2013
Thanks..it works.. I hv got a circle on pupil for which I need spatial coordinates.
Image Analyst
Image Analyst el 6 de Nov. de 2013
Why? The binary already is the coordinates. You don't need the x,y or row,col coordinates unless you are going to do some kind of inefficient loop instead of the faster vectorized method. Tell me what you want to do and I can help you avoid slowing down your program by looping over x,y or col,row.

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Jan
Jan el 6 de Nov. de 2013
Use find()
e.g.
A = randn(100,100) > .5; % example binary image
[row col] = find( A == 1 );
res = [ row col ];
This should give you the locations of the pixels containing a '1' in the matrix res.
  2 comentarios
Image Analyst
Image Analyst el 6 de Nov. de 2013
res =[row col] is not (x,y) with your method - it's (y,x) because row = y and col = x.
Jan
Jan el 6 de Nov. de 2013
Editada: Jan el 6 de Nov. de 2013
right, that should read res=[col, row] and equals your answer.
However, I only saw your answer after I posted mine, so it's futile anyway.

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