Cell Array and Matrix polynimial

How do I subtract matrix polynomials? I want to subtract D which is a cell array from Y a matrix polynomial
syms s
X=[1 2 3 4; 5 6 7 8];
Y=(s-2)*X;
D = {[1 2 ] , [1 3] ; [1 6] , [5 2] };
M=Y-D
Currently i'm getting error for this code saying 'Error using mupadmex Cell input must have string contents.'

 Respuesta aceptada

Azzi Abdelmalek
Azzi Abdelmalek el 10 de Nov. de 2013
syms s
X=[1 2 3 4; 5 6 7 8];
Y=(s-2)*X;
D = {[1 2 ] , [1 3] ; [1 6] , [5 2] };
M=Y-cell2mat(D)

7 comentarios

RoboKid
RoboKid el 10 de Nov. de 2013
What if the size of matrix,cell2mat(D) doesn't match with Y. i.e for the same program what if D = {[1 2 7] , [1 3 8] ; [1 6 7] , [5 2 9] }
--Thanks
Azzi Abdelmalek
Azzi Abdelmalek el 10 de Nov. de 2013
Then you have to explain what you want ?
RoboKid
RoboKid el 10 de Nov. de 2013
I'm trying to solve generalized Bezout identity for MIMO system as mentioned in the following paper https://www.dropbox.com/sh/tokqmnjbs6m8nem/amHkp4MlVY. There I have to subtract Denominator matrix array D, from (s-2)*K (K is transpose of state feedback matrix). I need a generalized program , works for any D . Is there anyway other than cell2mat?
--Thanks
RoboKid
RoboKid el 10 de Nov. de 2013
Editada: RoboKid el 10 de Nov. de 2013
syms s X=[1 2 3 4; 5 6 7 8]; Y=(s-2)*X; D = {[1 2 ] , [1 3] ; [1 6] , [5 2] }; t=mat2cell(Y) M=gsubtract(t,D)
I modified the program as above so that both Y and D are cell. But the problem now is Y is of class 'sym' and D is of class 'Double' . Is there anyway to change the class of D to sym from Double.
--Thanks
Azzi Abdelmalek
Azzi Abdelmalek el 10 de Nov. de 2013
Sorry, I'am not following you
RoboKid
RoboKid el 10 de Nov. de 2013
Is there anyway to change the class of D to sym from Double.
Azzi Abdelmalek
Azzi Abdelmalek el 10 de Nov. de 2013
Editada: Azzi Abdelmalek el 10 de Nov. de 2013
cellfun(@(x) sym(x),D,'un',0)
In your case D is not double, it's cell

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Function Creation en Centro de ayuda y File Exchange.

Preguntada:

el 10 de Nov. de 2013

Editada:

el 17 de Mayo de 2015

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by