how do i jump to a previous line in a matlab program

44 visualizaciones (últimos 30 días)
Dilesh Maharjan
Dilesh Maharjan el 22 de Nov. de 2013
Respondida: Iosif el 13 de Nov. de 2022
clc
tini=[21;26;29;30;23];
x= [1,2,3,0,0;3 6 -3 tini(3) 3;0,0, -2,-7,4;0,0,8,-3,tini(4);4,-5,8,0,0];
invx= inv(x);
a= [9;-3;21;tini(4);-23];
t=invx*a;
x=t-tini;
minx = min (x)
if abs(minx)>=1
tini=t;
% i need to go to line 4 and replace tini values with recent ones
else
fprintf ('your final temp is\n')
t
end

Respuestas (3)

Walter Roberson
Walter Roberson el 22 de Nov. de 2013
You cannot jump to previous lines. Use a structure such as
tini = ....
while true
x = ....
...
if abs(minx) < 1 %reversed condition
disp(...)
break
end
end

Azzi Abdelmalek
Azzi Abdelmalek el 22 de Nov. de 2013
I am not sure that your code converge, maybe you want
clc
tini=[21;26;29;30;23];
minx=10;
while minx>=1
x= [1,2,3,0,0;3 6 -3 tini(3) 3;0,0, -2,-7,4;0,0,8,-3,tini(4);4,-5,8,0,0];
invx= inv(x);
a= [9;-3;21;tini(4);-23];
t=invx*a;
x=t-tini;
minx = min (abs(x)); % I changed this line
tini=t;
end
fprintf ('your final temp is\n')
t
  1 comentario
Dilesh Maharjan
Dilesh Maharjan el 25 de Nov. de 2013
thank you very much for your help.. this is what i was trying to do..

Iniciar sesión para comentar.


Iosif
Iosif el 13 de Nov. de 2022
D=input ('Βαθος νερου σε m ')
W=input ('Βαρος ανα μοναδα μηκους της γραμμης αγκυρωσης στο νερο σε N/m ')
Hex=input ('εξωτερικη φορτηση σε kn ')
dx=input ('οριζοντια μετατοπιση σε m ')
if dx/D>=0.3 && dx/D<=0.6
else
disp ('Δωσε διαφορετικη τιμη για το dx')
dx=input ('οριζοντια μετατοπιση σε m ')
end
I want to make my programm go to if after else and run that lines again until if line is satisfied

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by