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i want to implement this transformation formula on any image, give me code, links , tutorials related to it ?

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how i implement this formula on such kind of images friends plz help
  3 comentarios
chitresh
chitresh el 29 de Nov. de 2013
Editada: Walter Roberson el 30 de Nov. de 2013
this is the formula i am looking to implement and on such kind of images

Respuestas (3)

Image Analyst
Image Analyst el 29 de Nov. de 2013
I don't know what x and y are. If they are coordinates then this t value does not depend on the image pixel intensities at all, which strikes me as strange.
  10 comentarios
chitresh
chitresh el 30 de Nov. de 2013
here my x and y is the 2 dimension vector point can you tell how to find these vector points and here i is the user and n is the minutiae points, so guys now hope i am clear , i got all stuff on a paper...
Image Analyst
Image Analyst el 30 de Nov. de 2013
I hope my code helped you. It does what you want, even though I don't understand what you want represents, or why you want it. Does this solve everything for you now?

Roger Stafford
Roger Stafford el 29 de Nov. de 2013
Editada: Roger Stafford el 29 de Nov. de 2013
Chitresh, I can tell you what kind of mathematical problem your expression is a solution to. Let us have n x and y pairs
x = [x1,x2,x3,...,xn]
y = [y1,y2,y3,...,yn]
and suppose we want to find the line of regression through them - that is, to find constants a and b such that
sum((a*x+b-y).^2)
is a minimum. This is a least squares problem and the solution for the constant b is
b = (sum(x.^2)*sum(y)-sum(x)*sum(x.*y))/(n*sum(x.^2)-sum(x)^2)
which is precisely your expression.
I can only guess how this might apply to the fingerprint image you display. If the xi and yi pairs refer to pixel coordinates of the black areas, and if the coordinate origin is at the lower left corner of the image, then b would be the vertical distance above the bottom at the left side where the line of regression crosses. On the other hand if the origin is located in the center of the image, b would be the vertical distance above or below this origin where the regression line crosses a vertical line through that origin. I would have thought the expression for a would have at least as much significance in the image as with b, since it would give the slope of that line of regression.
There are probably several other possible meanings that the x and y pairs might possess with regard to the image. I think that is a puzzle you will have to crack. Note that when you do solve your puzzle, the above expression shows you how to implement it in matlab in one line.
  4 comentarios
chitresh
chitresh el 30 de Nov. de 2013
this is some kind of transformation formulae so do you have any idea or links or tutorials related to it

msahar
msahar el 30 de Nov. de 2013
I am also working on matlab image transformation, affine, rotations, point clouds, normal unifications. If you tell me in detail your problem, may be i can help you.
  2 comentarios
chitresh
chitresh el 30 de Nov. de 2013
10 degress between 0 and 180 degrees on each N x N square in the image. The important parameters for a gabor filter are its frequency, f, it’s standard deviations in both the x and y directions and its directional strength, gamma (multiplied by the y’2 term). The frequency, f, represents the inverse of the average number of pixels between ridge centers.
chitresh
chitresh el 30 de Nov. de 2013
Editada: chitresh el 30 de Nov. de 2013
i want to implement this i already implemented normalization formulae now i like to implement this

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