Simulink Integrator block: how to
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Hi:
I'm trying to figure out how exactly the integrator block (Simulink) works, I mean, How can be calculated manually? (e.g. if a ramp signal is integrated, a parabola is obtained)
Thanks.
Respuestas (2)
Andreas Goser
el 19 de Dic. de 2013
0 votos
Simplified, it is new_value equals old_value plus increase and the increase is gradient divided by step size. The question now is how deep you are in math, e.g. for an university student of engineering I would recommend different material than if you are going to college.
1 comentario
soko loko
el 19 de Dic. de 2013
ES
el 19 de Dic. de 2013
0 votos
What do you mean by how exactly? integration of ramp is indeed a parabola.. example y=mx, integration of y=integration(mx)=(mx^2/2) which is indeed a parabola's equation..
8 comentarios
ES
el 19 de Dic. de 2013
And as you might know, physical meaning of integration is area under a curve. So if you consider a ramp, if you add up the area under a ramp, it will increase in such a way following the curve of a parabola.
soko loko
el 19 de Dic. de 2013
Kaustubha Govind
el 19 de Dic. de 2013
How the integration is done depends on what solver you have chosen for your model. You may want to read Choose a Solver to see the various solvers and how they perform integration.
soko loko
el 19 de Dic. de 2013
Guy Rouleau
el 20 de Dic. de 2013
Those steps:
in MATLAB, type "edit ode45" and you will be able to make the the 1-1 mapping between equations in the above link and the MATLAB code.
soko loko
el 20 de Dic. de 2013
ES
el 20 de Dic. de 2013
You dont need an equation to integrate. As I said before, integration is merely area under curve. suppose your sample time is 0.1 seconds, so your time signal is [0,0.1,0.2,0.3,0.4,...]. Your Actual Signal may be [0,4,2.3,-3.4,3,...]. corresponding to the time values defined above. lets assume t1=time[0]=0; t2=time[0]=0.1; dt=t2-t1=0.1; signal has changed from 0.4 t0 2.3. This region is almost a trapezoid. area under this curve is a the area of trapezium within these lines(x=0 [for y-axis or t1=0],y=0[for x-axis], x=0.1 [for t2=0.1] and y=mx+c where m=2.3/0.4 indicating slope].. Thus the total area is calculated as an summation of such tiny areas.
Now what I have described above is simple, it is called trapezoidal integration. The normal integration is similar in concept but more continuous and more generic.
soko loko
el 20 de Dic. de 2013
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