How can I built a new matrix in a new method?

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Ayob
Ayob el 18 de En. de 2014
Comentada: Paul el 18 de En. de 2014
I have a matrix like Assem{1} which is equal to:
Assem{1}=[0 6 2 0 0 7 0 0 0 12 3 0 1]
My another matrix is:
C=[W1 W2 W3 W4 W5 W6 W7 W8 W9 W10 W11 W12 W13], (W1 to W13 are defined values)
I want to use " D(Assem{i})=C " to define a new matrix D which is assembeled by members of matrix C with the help of matrix Assem{1}.
But, As you see some members of Assem{1} have zero values and doesn't lead to any position in D. So, I want to clear members with zero values of matrix Assem{1} and it's equivalent members in matrix C in order to be able built my matrix with the method of " D(Assem{i})=C ".
So
Assem{1} shold change to Assem{1}=[6 2 7 12 3 1]
C should change to C=[W2 W3 W6 W10 W11 W13]
How can I do these two steps with Matlab matrix methods.
[Note: Assem{i} has different values, I mentioned Assem{1} for i=1 as an example]

Respuesta aceptada

Paul
Paul el 18 de En. de 2014
ind = find(Assem{1}==0);
Assem{1}(ind)=[];
C(ind)=[];
  2 comentarios
Ayob
Ayob el 18 de En. de 2014
This is not right . My program should find zero members in Assem{1} and then clear for example second member and fourth member in Assem{1} which are zero and then clear second and fourth members in matrix C whether they are zero or not.
Paul
Paul el 18 de En. de 2014
That code does exactly what you describe. If not, tell me why it's wrong according to you.

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