Using a cell array and a for loop

Hey guys, I have to do a cell array to strore some information about an animal and use a for loop to display that information and the result should look like this:

 Identification number: 1 
Gender: M 
Weight: 400 
Age: 4 
Treatment: 0

I've tried many thing and I dont get how to have to columns. This is what i've tried.

 rat_cell = {'number', 'sex', 'weight', 'age', 'treatment', 1, 'M', 400, 4, 0}; 
for i = 1:5
disp(rat_cell(i,:)) 
     for j = 1:5 
     disp (rat_cell (j,:)); 
end 
end

I dont get why it doesnt show 2 columns like its supposed to. Thanks

Answer 1

[Amit]

You can use you code with a little modification: First of all, you're showing first cell and then 5 cell from the beginning. This is not what you want.

rat_cell = {'number', 'sex', 'weight', 'age', 'treatment'; '1', 'M', '400', '4', '0'}; % Note I changed the numbers to string
for j = 1:5
  disp([rat_cell{1,i} ': ' rat_cell{2,i}]);
end

Answer 2

[Andrei Bobrov]

use struct array

rat_cell = {'number', 'sex', 'weight', 'age', 'treatment', 1, 'M', 400, 4, 0};
a = reshape(rat_cell,5,[])';
out = struct(a{:});

Answer 3

[Azzi Abdelmalek]

There are many errors in your code:

Why nested loop? you are using display function 30 times!

i=1:5 and j=1:5 , you will never reach the 6th element

rat_cell(i,:) : what does that mean?

The correct code:

rat_cell = {'number', 'sex', 'weight', 'age', 'treatment', 1, 'M', 400, 4, 0};
for i = 1:5
  disp([rat_cell{i} ':'  num2str(rat_cell {i+5})]);
end

But for such problems, it's better to use what Andrei proposed

[Riri]

rat_cell(i,:) means that you show the i row and all the elements of the column for the rat_cell matrix. and i just have 5 elements so i dont need to get to 6, but thank you

[Azzi Abdelmalek]

rat_cell is 1x10 cell array. There is one row and 10 columns. You needed to put the first cell near the sixth cell and the second near the seventh, and so on.

[Riri]

Ya you are right, i just checked that out. Thanks for the clarification.