PLEASE SOLVE THE EXPRESSION

PLEASE SOLVE THE EXPRESSION

y=2^2 + log?sinx

USING MATLAB.

[amit jain]

it would be y=2^2 + log pi sinx

Answer 1

[Walter Roberson]

What does your ? indicate?

If your expression is y = 2^2 + log(sin(x)) and you need to solve for x, then

y - 2^2 = log(sin(x))
exp(y - 2^2) = exp(log(sin(x))
exp(y - 2^2) = sin(x)
arcsin(exp(y - 2^2)) = x

You can do this mechanically in Matlab if you have the Symbolic toolbox.

If you need to solve it numerically for a given y, then consider solving the expression

2^2 + log(sin(x)) - y = 0

perhaps using fzero()

[amit jain]

actually ques is y=2^2 + log pi sinx

[Walter Roberson]

y - 2^2 = log(pi*sin(x))

exp(y - 2^2) = exp(log(pi*sin(x))

exp(y - 2^2) = pi*sin(x)

exp(y - 2^2)/pi = sin(x)

arcsin(exp(y - 2^2)/pi) = x