matrix ismember of another matrix

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alex
alex el 17 de Mzo. de 2014
Comentada: alex el 17 de Mzo. de 2014
hello!
i have
A=[1 2 3 4 5]
B=[2 4]
i want to create D=[1 3 5], which is the A without the elements of B
j=1;
A=[1 2 3 4 5];
B=[2 4];
C=ismember(A,B);
for i=1:5
if C(i)==0
A(j)=A(i);
j=j+1;
end
end
for i=1:3
D(i)=A(i);
end
the code above works fine,but i want to know if there is any other way to do this,for any matrices with any dimentions
Thank you very much!

Respuesta aceptada

per isakson
per isakson el 17 de Mzo. de 2014
Editada: per isakson el 17 de Mzo. de 2014
A=[1 2 3 4 5];
B=[2 4];
C = setdiff( A, B )
returns
C =
1 3 5
Not sorted:
C = setdiff( A, B, 'stable' );
.
This works with vectors, however, "any matrices with any dimentions" is a different story
  2 comentarios
alex
alex el 17 de Mzo. de 2014
thank you very much!
alex
alex el 17 de Mzo. de 2014
i have a problem here
A = 2:.1:15
B=[9.4000 10.4000]
C=setdiff(A,B)
the elements 9.4000 and 10.4000 are in the C
however,if B=[9.3000 10.3000] then the setdiff works fine.
any idea why this happens?

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