# Assign value zero to n elements of cell array

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Karl on 17 Mar 2014
Commented: Benjamin on 12 Dec 2019
Hi all,
I am declaring a cell array to hold some numeric and non numeric data. I want to set the first row, all columns, equal to the numeric value zero. Something like this:
myCell = cell(5, 500);
myCell{1,:} = 0;
Which gives the error:
The right hand side of this assignment has too few values to satisfy the left hand side.
I've tried a number of other things, none worked, so have resorted to doing it in a loop. It works, but I really don't like it. Is there a simple way I'm missing?
Cheers, Karl

Sean de Wolski on 17 Mar 2014
myCell(1,:) = {0}
• Left hand side: use () to keep it as cells not braces for extraction of the content of cells.
• Right handside: make 0 a 1x1 cell so that it can be stuck into all of the cells on the left via scalar expansion

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chris oj on 18 Oct 2018
This answer just helped me...thanks Sean.
Flavia Aluisi on 19 Nov 2019
This is valid also in the case where I have a cell with 10 columns and 71842 rows and I want to fill with the number one only the rows between 2695 and 2746 of column one?
Sean de Wolski on 19 Nov 2019
@Flavia something like
myCell(2695:2746, 1) = {1}

Jeffery Devereux on 7 Mar 2018
Nice! Thanks (Had the same issue) Never thought about using the curly brackets around the zero.

Parna Bhattacharya on 17 Mar 2018
Thanks;

#### 1 Comment

Benjamin on 12 Dec 2019
This also works:
A =
1 2 3
4 5 6
7 8 9
in order to zero the ith row: (i = 1)
A(1,:) = [0]
>> A =
0 0 0
4 5 6
7 8 9