Finding a cell in an array

Hi,

I have a large cell aray called "txt". I am looking for a cell that is in this array, but the location/name changes from time to time. But this cell is always located next to one that has "vehicle" in it. How do i go through the text array and find the "vehicle" cell, but index it so I actually grab the cell next to it since that is the one that I want?

Thanks

Answer 1

[dpb]

One way...should be a simpler one but it didn't come to me otomh just now...

c is a cell array around had for an earlier query; just added the word 'vehicle' inside the first location...

>> c
c = 
  'This is vehicle'    'Description 1234567890'
>> find(cellfun(@(x) ~isempty(strfind(x,'vehicle')),c))+1
ans =
   2
>> c(find(cellfun(@(x) ~isempty(strfind(x,'vehicle')),c))+1)
ans = 
  'Description 1234567890'
>>

Answer 2

[Dishant Arora]

idx = find(cellfun(@(x) isequal(x , 'vehicle') , testCell))+1;

[dpb]

OP says "...next to one that has "vehicle" in it." which I inferred to mean that isequal may fail. Maybe that means that's the only content, don't know, but otherwise yours and mine are "great minds..." :)

[Dishant Arora]

Probably you interpreted it right. Let the poster make a call on that.

[dpb]

Ayup...just pointing out the "why" of choosing the apparently more difficult route.

Answer 3

[Image Analyst]

Try ismember:

txt = {'aaa', 10; 'bbb', 20; 'vehicle', 30; 'ddd', 40}
% Find 'vehicle' in the first column of the above list of strings.
index = find(ismember(txt(:,1), 'vehicle'))
numberYouWant = txt(index, 2) % Extract second column in that row.