Alternative to the symbolic toolbox

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Dominika on 17 Apr 2014
Edited: Walter Roberson on 18 Apr 2014
I created GUI which at some point contains 'sym' function. Then I tried do make .exe file using Matlab Compiler. As far as I found out Matlab Compiler doesn't support Symbolic Toolbox. Now my question is: how can I deal with the problem?
I need to find fb_ value for which both formulas are equal, all other values are variables specified before. Does anyone have an idea of alternative way of solving the problem without using symbolic toolbox?
part of my code:
% Determine cut-off frequency fb
% sym fb_
-48 + 20*log10(m2*fb_)-48+20*log10(fb_*d)-29,fb_); % ref.(4), p.397
fb = double(fb_syn);
Thanks for any ideas!

Answers (1)

Walter Roberson
Walter Roberson on 17 Apr 2014
Solve the form ahead of time.
It is easier to solve general forms when one uses rational values instead of floating point such as -47.3 . But if you substitute 473/100 and solve then the reasons for various constants that show up in the solution become obscured. So for the moment substitute a variable, V, for the -47.3, declare all the names involved as syms, and solve. simplify() and expand() and simplify() again. What you can get out will look like,
fb_ = 1000*10^(-(1/40) * V + (1/40) * deltaTL + 1/8) * (m1+m2)^(1/2) / (m2^(1/2) * d^(1/2) * m1^(1/2))
Once you have that formula you can put it into the source code, eliminating the solve() call.
Walter Roberson
Walter Roberson on 18 Apr 2014
Edited: Walter Roberson on 18 Apr 2014
Which MATLAB version do you have? simplify() is defined through MATLAB; see
syms fb_ V deltaTL m1 m2 d
FB = simplify(expand(simplify(solve(fb_ = 1000*10^(-(1/40) * V + (1/40) * deltaTL + 1/8) * (m1+m2)^(1/2) / (m2^(1/2) * d^(1/2) * m1^(1/2)), fb_))));
You can even proceed from there to use matlabFunction() to generate .m code into a file that you could then invoke from your executable.

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