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Finding signal to noise ratio

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Tinkul
Tinkul el 8 de Mayo de 2014
Comentada: cbentter el 2 de Abr. de 2020
I have a signal x=[34;56;12;87;35]
I have added some noise with the signal x. After denoising i have got the output
x0=[ 33.88;55;11.11;86.77;34.99]
Now how can i find out SNR? please help....

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Sven
Sven el 8 de Mayo de 2014
Editada: Sven el 8 de Mayo de 2014
Hi Tinkul, does this help you out? I assume that the values you gave are already in your desired units (although true SNR is based on power of signals, not necessarily the signals themselves)
signal = [34;56;12;87;35]
response = [ 33.88;55;11.11;86.77;34.99]
noise = response - signal
rawratio = signal ./ abs(noise)
snr = 10*log10(rawratio)
ans =
24.5230
17.4819
11.2979
25.7779
35.4407
This shows that in your observations the signal is in the order of hundreds of times greater than the noise between true and measured response (in the rawratio variable). Signal-to-noise ratio is often (usually) given in decibels (db) which is 10log10(signal/noise)
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cbentter
cbentter el 2 de Abr. de 2020
But if you only have the signal with the noise?

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