Help me about the error with symsum function to calculate the sum of series ?
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George Papazafeiropoulos on 28 May 2014
Maybe because there is not any analytical formula which gives this sum. Can this function be integrated in an analytic way? I suppose no.
You can take the numerical result of the sum in this way:
sum1=sum(((k+1).^(1/2) - (k-1).^(1/2))./k.^2);
sum2=sum(((k+1).^(1/2) - (k-1).^(1/2))./k.^2);
and compare sum1 and sum2. The result is 1.763306701885209.