Indexing high dimension elements from a N-D matrix
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Junhong YE
el 28 de Mayo de 2014
Comentada: Matt J
el 28 de Mayo de 2014
Hi, all,
I met a problem when I was trying to index the third dimension elements of a 3-dim matrix, i.e.
A=rand(10,10,10);
B=A(1,1,:);
, I found B was not a vector as I expected, but rather, a 1-by-1-by-10 array. But A(:,1,1) and A(1,:,1) return a column and row vector respectively.
I wonder why MATLAB is designed in this way and how to obtain what I want ?
I know a workaround is use squeeze(A(1,1,:)), which ignores the singleton dimensions. Is there any other more direct way?
Thanks.
1 comentario
Matt J
el 28 de Mayo de 2014
I wonder why MATLAB is designed in this way
As you already pointed out, A(:,1,1) and A(1,:,1) are not the same shape and have singleton dimensions where you provided singleton subscripts. If that makes sense to you, why should A(1,1,:) obey a different rule?
Respuesta aceptada
Más respuestas (0)
Ver también
Categorías
Más información sobre Matrix Indexing en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!