textscan trouble: starting file position on re-read
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
I'm trying to read a data file of integers. The file is formatted as follows:
-112-999-999-999-555
-999-999
-777 0 0 0 0
0 20
-757 11 0 0 0
0 0
There are 3 blocks of 7 numbers each.
I tried
fid=fopen('filename.txt')
textscan(fid,'%4d',7)
And got the following as expected.
-112
-999
-999
-999
-555
-999
-999
But then I issue   textscan(fid,'%4d',7)   again. I would expect to get the second block this time, but instead I get:
2
-999
-999
-999
-555
-999
-999
It seems textscan started reading at the wrong place (not where it left off).
Any thoughts why it's doing this?
Thanks, David
Respuestas (1)
Image Analyst
el 20 de Jun. de 2014
In your second call to textscan() your first argument is fww. What is that? Why are you not using fid like in the first call to textscan()????
9 comentarios
Stephen23
el 10 de Oct. de 2014
Editada: Stephen23
el 10 de Oct. de 2014
Tested with MATLAB R2012b. I downloaded your data file filename.txt, and ran the following code:
>> fid = fopen('filename.txt');
>> A(1) = textscan(fid,'%4d',7);
>> A(2) = textscan(fid,'%4d',7);
>> fclose(fid);
>> [A{:}]
ans =
-100 -106
-101 107
-102 108
-103 0
-555 0
-104 0
-105 20
This seems to give the outputs you want.
per isakson
el 10 de Mayo de 2015
Editada: per isakson
el 10 de Mayo de 2015
With 2014a
ans =
-100 0
-101 -101
-102 -102
-103 -103
-555 -555
-104 -104
-105 -105
was this ever reported?
Ver también
Categorías
Más información sobre Data Import and Export en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!