Plotting a 2D matrix

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Alok Pathak
Alok Pathak el 27 de Jun. de 2014
Comentada: Gnaneswar Nadh satapathi el 27 de Jun. de 2014
I need to plot a matrix M which is 300*42 in size. On the X axis I need to plot 1:42. On the Y Axis I need to plot the value corresponding to the 42 values. On the Z axis I need to plot the 1:300 value.
I tried using the plot3 function in a loop like this and I wouldnt get it right :
for i = 1:300
plot( 1:42, M(i, 1:42), 1:i);
hold on;
drawnow ;
end
I get the error Vectors are not of similar lengths. Please Help. Many thanks
Regards
  3 comentarios
Alok Pathak
Alok Pathak el 27 de Jun. de 2014
The Idea is this. I have recorded a vector of length 42. I have done this process for 300 times. I want to show how the vector changes while i record the vector 300 times. I wanted to show a 3d plot that carries this information.
The vectors are of similar lengths. 1: 42 and M(i,1:42) are both 1*42 double.
Regards
Gnaneswar Nadh satapathi
Gnaneswar Nadh satapathi el 27 de Jun. de 2014
plot it as
surf(M)

Iniciar sesión para comentar.

Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 27 de Jun. de 2014
Editada: Andrei Bobrov el 27 de Jun. de 2014
s = size(M);
[z,x] = ndgrid(1:s(1),1:s(2));
data = permute(num2cell(cat(3,x,M,z), 2),[3,2,1]);
plot3(data{:});
or
s = size(M);
[x,z] = ndgrid(1:s(2),1:s(1));
plot3(x,M.',z);

Más respuestas (1)

David Sanchez
David Sanchez el 27 de Jun. de 2014
Maybe you are thinking no something like this:
M=rand(300,42); % your data here
[xx, yy] = meshgrid(1:42,1:300);
plot3(xx,yy,M,'*')

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