ismember error

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joseph Frank
joseph Frank el 16 de Ag. de 2011
Hi,
x0=find(ismember(A,B)==1) is giving me error ??? Error using ==> cell.ismember at 28 Input must be cell arrays of strings.
A is a cell array that has the following format: '580135' '803111' '803111' '803111' '373298' '373298'
Bis a 1x1 cell wit the following format 377298;
I don't know why A has '' and B doesn't ,which could be the source of error.

Respuestas (2)

Paulo Silva
Paulo Silva el 16 de Ag. de 2011
It works just fine in this example, you also don't need the ==1 in the find argument.
A={'580135' '803111' '803111' '803111' '377298' '373298' '373298'}
B={'377298'}
find(ismember(A,B))

Walter Roberson
Walter Roberson el 16 de Ag. de 2011
Please clarify whether the content of B{1} is numeric or a string. It would need to be a string for this purpose.
Is this an example, with more values of B to be added later, or are you looking to find B within A? If you are looking to find B within A then you would use ismember(B,A)
The == 1 is redundant with ismember() as it is all 0 or 1 anyhow. find(ismember(A,B))
  2 comentarios
joseph Frank
joseph Frank el 16 de Ag. de 2011
B sometimes is a number and sometimes is a string, find(ismember(A,B))is what i need but it gives the above mentioned error
Jan
Jan el 16 de Ag. de 2011
@Joseph: Then ISMEMBER is *not* what you need. It cannot compare strings with numbers. What do you expect as result of such a comparison?

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