Vibration of a Cantilever beam

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Bhanu Pratap Akherya
Bhanu Pratap Akherya el 25 de Ag. de 2021
Respondida: Umang Pandey el 19 de Abr. de 2024
here is my main code:
clear all
clc
Ne=6;
l=1; %length
t=0.02; %thickness
b=0.02; %width
modulus=2e11; %(E)
area=b*t;
imoment=(b*((t)^3))/12;
Le=l/Ne; %length of element
Rho=7850; %density
%Element stiffness matrix
K1=(modulus*imoment/(Le^3))*[12,6*Le,-12,6*Le; ...
6*Le,4*Le*Le,-6*Le,2*Le*Le; ...
-12,-6*Le,12,-6*Le; ...
6*Le,2*Le*Le,-6*Le,4*Le*Le];
Kglobal=zeros(2*(Ne+1),2*(Ne+1));
M1=[156 22*Le 54 -13*Le;...
22*Le 4*Le*Le 13*Le -3*Le*Le;...
54 13*Le 156 -22*Le;...
-13*Le -3*Le*Le -22*Le 4*Le*Le]*(Rho*Le*b*t)/420;
Mglobal=zeros(2*(Ne+1),2*(Ne+1));
for ii=1:Ne
Kglobal(2*ii-1:2*(ii+1),2*ii-1:2*(ii+1))=Kglobal(2*ii-1:2*(ii+1),2*ii-1:2*(ii+1))+K1;
Mglobal(2*ii-1:2*(ii+1),2*ii-1:2*(ii+1))=Mglobal(2*ii-1:2*(ii+1),2*ii-1:2*(ii+1))+M1;
end
K=Kglobal;
K(1:2,:)=[];
K(:,1:2)=[];
M=Mglobal;
M(1:2,:)=[];
M(:,1:2)=[];
C=0.05*Kglobal;
C(1:2,:)=[];
C(:,1:2)=[];
K
M
C
u=(2*Ne)+1;
%dt=1/(max_freq*20);
dt=0.001;
T=300;
%Displacement initials
y0=zeros(2*(2*(Ne+1))-4,1);
% y0(1:2,:)=[];
% y0(u:u+1,:)=[];
y0(end-1,1)=0.5;
% t_array = a(1,:); % This is t array from xls file
F=xlsread('l&d.xlsx','O1:O300'); % This is F array from xls file
%% ode solver
for i = 1:length(F)
[tsol ysol]=ode15s(@(t, y) beam_function(t, y, F(i), K, M, C, u),[1:dt:T],y0);
end
ysol(:,u:end)=[];%eliminate velocity nodes 5001*12
size(ysol)
ii=1:2:(u-2); %eliminate angular displacement nodes
ysol(:,ii+1)=[]; %eliminating angular dis components
size(ysol)
%% plotting
plot(tsol,ysol(:,Ne))
here is my function
function [dy]=beam_function(t, y, F, K, M, C, u)
dy=[y(u:end);
M\(F-K*y(1:u-1)-C*y(u:end))]
Right now the force seems to be applied on the complete beam at once.
I want force (F) to be applied only on the last node, like the case of a cantilever beam. Can someone tell me a way how i can do that?

Respuestas (1)

Umang Pandey
Umang Pandey el 19 de Abr. de 2024
Hi Bhanu,
To apply the force only on the last node of the beam, like in a cantilever beam scenario, you need to adjust the way the force is incorporated into your system of equations within the beam_function. Given that the force F is read from an Excel file and is intended to be applied at discrete time steps, you should construct a force vector that applies this force only to the last node.
Here's how you can modify your beam_function to apply the force only to the last node:
function [dy]=beam_function(t, y, F, K, M, C, u)
% Initialize force vector of size u-1 (since you've removed the first two DOFs)
F_vec = zeros(u-1, 1);
% Apply the force to the second last entry, which corresponds to the last node's displacement
% This is because the last entry would correspond to the rotation at the last node
F_vec(end-1, 1) = F;
% Dynamics equation
dy=[y(u:end);
M\(F_vec-K*y(1:u-1)-C*y(u:end))];
end
This adjustment ensures that the external force F (read from the Excel file at each time step) is applied only to the displacement of the last node, accurately simulating a cantilever beam subjected to a point load at its free end.
Best,
Umang

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