How to use dlgradient for computing second derivative?

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The following code gives me an error.
x0 = dlarray([-1,2]);
[fval,gradval] = dlfeval(@rosenbrock,x0)
function [y,dy2dx] = rosenbrock(x)
y = 100*(x(2) - x(1).^2).^2 + (1 - x(1)).^2;
dydx = dlgradient(y,x);
dy2dx= dlgradient(dydx,x);
end
I am using dlgradient to compute the second derivative but getting the following error:
"Error using dlfeval (line 43)
Value to differentiate must be a traced dlarray scalar."
Any help on what am i doing wrong? Thanks.

Respuesta aceptada

Abolfazl Chaman Motlagh
Abolfazl Chaman Motlagh el 10 de Sept. de 2021
Hi, You are using dlgradient wrong, first agument of dlgradient should be scalar. after 1 gradient from y respect to x. gradient return 1by2 vector. they are and . so you cannot use dydx again in dlgradient. also for second derivative you have 4 elements : , , ,
also you should specify option EnableHigherDerivatives in dlgradient.
so substiture your function with this :
function [y,dy2dx] = rosenbrock(x)
y = 100*(x(2) - x(1).^2).^2 + (1 - x(1)).^2;
dydx = dlgradient(y,x,'EnableHigherDerivatives',true);
dy2dx(1,1:2)= dlgradient(dydx(1),x);
dy2dx(2,1:2)= dlgradient(dydx(2),x);
end
  5 comentarios
Sanaz Zanjani Foumani
Sanaz Zanjani Foumani el 29 de Dic. de 2021
Do you know how I can use dlgradiet in fmincon? I mean I want to use automatic derevative in fmincon insted of analytical derevative.

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