sum different cell arrays based on index

Hello, i have

A = { [0,1,0; 0,0,0; 0,0,0],...

[1,0,0; 0,0,0; 0,1,1],...

[0,0,0; 0,1,0; 0,0,0],...

[0,0,0; 0,1,0; 0,0,0],...

[0,0,1; 0,0,0; 1,0,0],...

[1,1,0; 0,0,0; 0,0,0],...

[0,0,0; 0,0,1; 0,0,0]} ;

and i = { [1,2,3], [4,5,6,7] }

i need to sum A based on index groups resulting B={ [1,1,0; 0,1,0; 0,1,1], [1,1,1; 0,1,1; 1,0,0] }, how can i do this?

[Stephen23]

F = @(x)sum(cat(3,A{x}),3);
B = cellfun(F,id,'uni',0);
celldisp(B)

B{1} =
     1     1     0
     0     1     0
     0     1     1
B{2} =
     1     1     1
     0     1     1
     1     0     0

Answer 1

[KSSV]

A = { [0,1,0], [1,0,0], [0,0,0], [0,0,0], [0,0,1], [1,1,0], [0,0,0]} ;
id = { [1,2,3], [4,5,6] } ; 

n = length(id) ; 
iwant = cell(n,1) ; 
for i = 1:n
    iwant{i} =  sum(vertcat(A{id{i}})) ; 
end
celldisp(iwant)

 
iwant{1} =
 
     1     1     0

 
 
iwant{2} =
 
     1     1     1

 

[Sule Anjomshoae]

thank you for your answer, but i realise there was a mistake in my question and now i editted it. Could you please revise your answer if possible? many thanks.

[KSSV]

The same logic with few changes applies:

A = { [0,1,0; 0,0,0; 0,0,0],... 
      [1,0,0; 0,0,0; 0,1,1],...
      [0,0,0; 0,1,0; 0,0,0],... 
      [0,0,0; 0,1,0; 0,0,0],...
      [0,0,1; 0,0,0; 1,0,0],... 
      [1,1,0; 0,0,0; 0,0,0],...
      [0,0,0; 0,0,1; 0,0,0]} ;
id = { [1,2,3], [4,5,6,7] } ;


n = length(id) ; 
iwant = cell(n,1) ; 
for i = 1:n
    iwant{i} =  sum(cat(3,A{id{i}}),3) ; 
end
celldisp(iwant)

 
iwant{1} =
 
     1     1     0
     0     1     0
     0     1     1

 
 
iwant{2} =
 
     1     1     1
     0     1     1
     1     0     0

 

[Sule Anjomshoae]

Thank you!