how to develope loop to save the 'n' elements from the vectors
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
clc;
clear;
A= [14,51,2,15,........,7 ] % this is known
p1=A[1]
p2=A[2]
.
.
.
.
.
pn=A[n]
%%% i need to use p1,p2,p3,...pn in another equation. so i dont know to to save this elements from A. how to use loop to that it automatically get saved for n elements
0 comentarios
Respuestas (2)
Matt J
el 15 de Sept. de 2021
It is not a good idea to store A(i) in separate variables. You should probably just write your equation in terms of vector operations on A, which you already have.
2 comentarios
Matt J
el 15 de Sept. de 2021
A(1)*r^2+A(2)*ln(r)+A(3)*cos(theta)/r+A(4)*sin(theta)/r+(A(n)*r^(-n+2))*cos(n*theta)
Awais Saeed
el 15 de Sept. de 2021
Although it is not prefered to name variables in a loop but if you striclty want to do this in loops than you can use eval(). Note that using this method is NOT RECOMMENDED. It has been said many times in this forum and by MATLAB itself.
clc;
clear;
A= [14,51,2,15,7]
for col = 1:1:size(A,2)
eval(['p',num2str(col),'=A(',num2str(col),')'])
end
1 comentario
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!