Add missing numbers of 0's and 1's in an array

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kamel attafkamel
kamel attafkamel el 26 de Sept. de 2021
Respondida: Akira Agata el 26 de Sept. de 2021
hello, I have a sequence of 1's and o's values.
Example: I have an 1D array which looks like:
[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0]
What I want is to count elements connected to each other and if(mod(elements connected to each other ,10)>5 then add (10-mod) of 1's or 0's
the result can be something like this:
[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0].
  1 comentario
Walter Roberson
Walter Roberson el 26 de Sept. de 2021
Editada: Walter Roberson el 26 de Sept. de 2021
Jan has a File Exchange contribution for Run Length Encoding.
Once you know the counts, it is easy to modify the counts in the data and then ask to do run length decoding.

Iniciar sesión para comentar.

Respuestas (2)

Walter Roberson
Walter Roberson el 26 de Sept. de 2021
M = [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0];
zstarts = strfind([1 M], [1 0])
zstarts = 1×2
1 24
zend = strfind([M 1], [0 1])
zend = 1×2
16 31
zlengths = zend - zstarts + 1
zlengths = 1×2
16 8
ostarts = strfind([0 M], [0 1])
ostarts = 17
oends = strfind([M 0], [1 0])
oends = 23
olengths = oends - ostarts + 1
olengths = 7
if zstarts(1) ~= 1; zlengths = [0 zlengths]; end
runs(1:2:length(zlengths)*2-1) = zlengths;
runs(2:2:length(olengths)*2) = olengths;
mods = mod(runs,10);
mask = mods > 5;
runs(mask) = ceil(runs(mask)/10)*10;
runs
runs = 1×3
20 10 10
elements = zeros(1,length(runs));
elements(2:2:end) = 1;
newM = repelem(elements, 1, runs);
num2str(newM)
ans = '0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0'

Akira Agata
Akira Agata el 26 de Sept. de 2021
How about the following?
% Sample data
x = [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0];
% Calculate run-length for each element
idx = diff(x) ~= 0;
idx = [true,idx];
g = cumsum(idx);
group = g(idx)';
element = x(idx)';
lengthIn = accumarray(g',1);
% if mod(length,10)>5, add(10-mod(...))
lengthOut = lengthIn;
idx = mod(lengthIn,10) > 5;
lengthOut(idx) = lengthOut(idx) + (10-mod(lengthIn(idx),10));
% Summarize the result
tSummary = table(group,element,lengthIn,lengthOut);
% >> tSummary
% tSummary =
% 3×4 table
% group element lengthIn lengthOut
% _____ _______ ________ _________
% 1 0 16 20
% 2 1 7 10
% 3 0 8 10
% Then, create the output based on the tSummary
c = arrayfun(@(ele,len)repelem(ele,1,len), tSummary.element, tSummary.lengthOut,...
'UniformOutput', false)
x2 = cell2mat(c');

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