extraction oval-like part from segmented image?

3 visualizaciones (últimos 30 días)
Nisreen Sulayman
Nisreen Sulayman el 7 de Ag. de 2014
Comentada: Image Analyst el 10 de Ag. de 2014
How to extract oval-like part in a vessel segmented image?
I want to extract the oval-like part in the middle of a segmented vessel image
image: https://copy.com/GT6n8EF82BKw)
I want to:
- compute the Distance Transform from black.
- Apply a Local Max to the Distance Transform.
- For each of those candidates, create a histogram of gradient angles. Try a 15x15 local
neighborhood, and a bin-size of 30 degrees (12 bins). Compute the standard deviation of the
histogram. the candidate with the lowest standard deviation would be the center of an aneurysm.
I have been stuck for long time,Could you please answer me or redirect my question to someone who can help.
Thank you in Advance
**************
If you some one know an active "Image Processing using MATLAB" groups, please add me

Respuesta aceptada

Image Analyst
Image Analyst el 9 de Ag. de 2014
Please define, outline, or somehow indicate the "oval-like part" that you'd like to extract or segment out.
  2 comentarios
Image Analyst
Image Analyst el 10 de Ag. de 2014
I'd try an opening to detach the thing. Then I'd label the image and call regionprops. Ask for area, Euler number, and perimeter. Filter the results to get blobs that have an Euler number of 1 (meaning no holes) and a circularity of 3-5 or so (or smaller).
circularity = (perimeter .^2 )/ (4*pi*area)
You might also have to filter based on an area, like areas between 200 0and 2000 pixels or so. Measure everything and see what values your blob takes on and what the other blobs take on. Use ismember() to do the filtering if you want an image with only that blob in it.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Image Segmentation and Analysis en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by