Borrar filtros
Borrar filtros

Wrong equastion of XY dependence

1 visualización (últimos 30 días)
Pavol Namer
Pavol Namer el 7 de Ag. de 2014
Comentada: Pavol Namer el 7 de Ag. de 2014
Hi I try to solve following problem.
I try to type following equastion of XY dependence:
x= [-5,15]
a= 1
b= 12
c= 2.4
r= 1
y= -1*(a-b*(((x)-r)).^4).*(exp(-1*c*((x)-r).^2))
figure
plot (x,y)
it should be this equation:
And it should have this shape of XY dependence
But it give me the wrong shape (like linear XY dependence).
Can anybody advise, where the mistake i?
Thank you
P.

Respuesta aceptada

Mischa Kim
Mischa Kim el 7 de Ag. de 2014
Editada: Mischa Kim el 7 de Ag. de 2014
Use,
x = -5:0.1:15; % create a vector x, element spacing: 0.1
a = 1;
b = 12;
c = 2.4;
r = 1;
y = -1*(a-b*(((x)-r)).^4).*(exp(-1*c*((x)-r).^2));
figure
plot(x,y)
The only difference is in the first line. In your code you evaluate y only twice, at x = -5 and at x = 15.
  1 comentario
Pavol Namer
Pavol Namer el 7 de Ag. de 2014
Oh my got :) Thanks a lot, I am totaly stupid guy :))

Iniciar sesión para comentar.

Más respuestas (1)

David Sanchez
David Sanchez el 7 de Ag. de 2014
Instead of your definition of x, try the folowing one:
x= -5:.01:15; % array of 2001 elements, your definition were a mere 2 element array
a= 1;
b= 12;
c= 2.4;
r= 1;
y= -1*(a-b*(((x)-r)).^4).*(exp(-1*c*((x)-r).^2));
figure
plot (x,y)

Categorías

Más información sobre Interactive Control and Callbacks en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by