Inline Indexing to Dynamic Field Names
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
How can I integrate and index function output into dynamic field names?
Example:
Say function y=fun(x) outputs an array of integers.
How can I implement:
Varnames=['var1' 'var2' 'varx' 'vary'];
TestStruct.(Varnames(index(fun(x),3))) = 0;
that is equivalent to: (for instance)
TestStruct.varx = 0;
or better yet, if varx is an array, a way to make it equivalent to:
TestStruct.varx(n) = 0;
Is there a way to tell a function that you are only interested int the nth element?
Thanks in advance,
0 comentarios
Respuesta aceptada
Oleg Komarov
el 8 de Sept. de 2011
I felt Walter was a challenge, I shouldn't be suggesting stuff like this...
Varnames = {'var1', 'var2', 'varx', 'vary'};
x = [2 4 1 3];
n = 3;
TestStruct.(Varnames{x*accumarray(n,1,[numel(x),1])}) = 0
or better
s = struct('type','()','subs',{{n}});
TestStruct.(Varnames{subsref(x,s)}) = 0
Más respuestas (1)
Chaowei Chen
el 31 de Ag. de 2011
Varnames={'var1', 'var2', 'varx', 'vary'};
%if varx is scalar
TestStruct.(Varnames{1,3}) = 0
%if varx is array
TestStruct=struct(Varnames{1,3},zeros(10,1))
4 comentarios
Jan
el 8 de Sept. de 2011
@Sean: You can't. Do not waste time with searching for an inline version. Simply use a FOR loop to access a list of fields.
Walter Roberson
el 8 de Sept. de 2011
Well, you can. But it is ugly and obscure and would have even experienced MATLAB programmers trying to figure out what is going on. A simple loop would be shorter, faster, and much much clearer.
Ver también
Categorías
Más información sobre Function Creation en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!