Random number generation from uniform distribution

Good afternoon, I'm currently trying to generate random numbers from a uniform distribution, but I'm not sure how to input probabilities.

For example, Let S be uniformly distributed between 70 and 130:

a=70; 
b=130;
S=a+(b-a).*rand

However, let's say we want to generate T which is uniformly distributed: between 0.1 and 1.0 (with probability 0.75) between 1.0 and 5.0 (with probability 0.25)

Is it possible to use the rand function as normal? i.e.

a=0.1;
b=1.0;
c=5.0
T=([a+(b-a).*rand]*0.75)+([b+(c-b).*rand]*0.25)

I appreciate any feedback.

[dpb]

T=([a+(b-a).*rand]*0.75)+([b+(c-b).*rand]*0.25)

No, that's scaling the return value by the two probabilities, not the frequency. Need to scale values returned from rand <0.75 to range [a,b] and the rest to [b,c]

Answer 1

[the cyclist]

N = 1000000;

a=0.1;
b=1.0;
c=5.0;

r1 = rand(N,1);
r2 = rand(N,1);

T=(a+(b-a).*r1).*(r2<=0.75) + (b+(c-b).*r1).*(r2>0.75);

figure
hist(T,0.105:0.01:4.995)

[Ronan]

Thank you very much for your help, the cyclist. Greatly appreciated! :)