# How do I output the values of a function in a vector string to plot a graph?

4 views (last 30 days)
Red on 11 Oct 2021
Commented: Mathieu NOE on 5 Nov 2021
A = 1;
df = 100000;
F = df/4;
n = 2^3;
t = [0:n-1]/df;
s = A*sin(2*pi*F*t);
S = reshape(s,4,[]);
Y1 = sum(S(1,:)-S(3,:));
Y2 = sum(S(2,:)-S(4,:));
Y = sqrt(Y1^2+Y2^2);
TT = max(t)/4*df;
Porog = 2*TT*2*A;
As a result, Y will be equal to 4 in this case. I want to plot Y versus n. And in principle any other. Just assigning for n = 2 ^ 3: 2 ^ 4: 2 ^ 5 doesn't work. How to get, depending on n, a set of all variables, including Y in the form of a row vector. And build a graph. Did not understand. Help me please. That is, (Y = 500, n = 5), (Y = 800, n = 10).

Mathieu NOE on 13 Oct 2021
hello
maybe this ? (tested OK on my side)
clc
clearvars
A = 1;
df = 100000;
F = df/4;
% n = 2^3;
n = 2 ^ 3: 2^ 4 : 2 ^ 5;
for ci = 1:numel(n)
t = [0:n(ci)-1]/df;
s = A*sin(2*pi*F*t);
S = reshape(s,4,[]);
Y1 = sum(S(1,:)-S(3,:));
Y2 = sum(S(2,:)-S(4,:));
Y(ci) = sqrt(Y1^2+Y2^2);
TT(ci) = max(t)/4*df;
Porog(ci) = 2*TT(ci)*2*A;
end
plot(n,Y);
##### 2 CommentsShowHide 1 older comment
Mathieu NOE on 5 Nov 2021
hello
do you mind accepting my answer ?
tx

R2020b

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