Sorting cell array based on distance
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Pelajar UM
el 18 de Oct. de 2021
Comentada: KSSV
el 18 de Oct. de 2021
I have two cell arrays that contain information about the x,y,z coordinates for points in space. These data are random and do not necessarily follow any sequence.
Example of data1:
-512.7269 -223.8000 -256.1018
-509.1519 -223.8000 -263.4274
-512.9410 -223.8000 -256.3643
-508.8008 -223.8000 -263.5808
-521.0831 -223.8000 -263.1835
-520.0226 -223.8000 -259.8741
-505.0888 -223.8000 -251.5124
-504.7663 -223.8000 -251.4452
Example of data2:
-500.2925 -178.0828 -260.5501
-500.3713 -177.7340 -259.0459
-500.4465 -177.1616 -257.6118
-500.5162 -176.3785 -256.2803
-500.5790 -175.4029 -255.0823
-500.6334 -174.2572 -254.0454
-500.6780 -172.9680 -253.1935
-500.7120 -171.5645 -252.5458
I am trying to sort the data so that the nearest points in space appear in the same sequence of rows.
This is how the code looks like so far. It calculates the minimum distance for combination of every 2 points and then sort this distance in an ascending fashion. What is missing is the part that updates 'data1' to follow the same sequence.
data1 = importdata ('nodes.txt')
Xi = data1(:,1);
Yi = data1(:,2);
Zi = data1(:,3);
data2 = importdata ('TT_angleBlock_nodes.csv')
Xt = data2(:,1);
Yt = data2(:,2);
Zt = data2(:,3);
input = [Xi,Yi,Zi];
output= [Xt,Yt,Zt];
for row = 1 : 1:row
deltaX = output(row,1) - input(:,1);
deltaY = output(row,2) - input(:,2);
deltaZ = output(row,3) - input(:,3);
% Pythagorean Theorem
distances = sqrt(deltaX .^2 + deltaY .^ 2 + deltaZ .^ 2);
minDistance(row) = min(distances);
Dist = sort (minDistance);
end
0 comentarios
Respuesta aceptada
KSSV
el 18 de Oct. de 2021
Read about knnsearch. This will give you the nearest points from a set points for a given point. This will work for you.
4 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Cell Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!