Empty figure when trying to plot in a for loop

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Jonas Freiheit
Jonas Freiheit on 22 Oct 2021
Commented: Stephen on 22 Oct 2021
Hi all,
I was wondering why I am presented with an empty figure when trying to plot in a for loop. My x and y variables seem to be correct and are changing scalar values for every part of the for loop.
My code below is as follows:
clear, clear all, clc
vacuum_permittivity = 1; %Defines epsilon 0 value = 1
for num = 1:11 %Initialises for loop to the length of number_of_point
number_of_point=11:4:51; %Initialises array of the number of points
number_of_points=number_of_point(num); %Selects the part of the number of points array to use for the conditions below
x_1 = -5; %Defines the minimum x axis value
x_N = 5; %Defines the maximum x axis value
x = transpose(linspace(x_1, x_N, number_of_points)); %Transposes x as a matrix with N number of points
y = x; %Defines the x dimensions to be equal to the y dimensions
h = x(2) - x(1); %Finds the 'h' value as the spacings between the points
[X, Y] = meshgrid(x,y); %Initialises the meshgrid for the
electricpotential_analytic=(X.^2+Y.^2).*exp(-X.^2-Y.^2); %Defines the analytical electric potential
sigma=exp(-X.^2-Y.^2).*(12*X.^2-4*X.^2.*(X.^2+Y.^2)+12*Y.^2-4*Y.^2.*(X.^2+Y.^2)-4); %Defines the analytical charge density
% Define our differential operator for two dimensions as a matrix.
A = (1 / h^2) * (diag(ones(1, number_of_points - 1), 1) + ...
diag(-4 * ones(1, number_of_points), 0) + ...
diag(ones(1, number_of_points - 1), -1));
B = (1 / h^2) * diag(ones(1, number_of_points), 0);
L = kron(diag(ones(1, number_of_points), 0), A) + ...
kron(diag(ones(1, number_of_points - 1), 1), B) + ...
kron(diag(ones(1, number_of_points - 1), -1), B);
sigma = reshape(sigma, number_of_points^2, 1); %Reshapes sigma to have the same dimensions as the electric potential
electricpotential_analytic=reshape(electricpotential_analytic,number_of_points^2,1); %Reshapes the electric potential to have the same dimensions as sigma for a matrix
electric_potential=-inv(L)*sigma; %Uses equation 39 to define Poisson's equation in matrix format. No element wise multiplication is done since are interested in the error in scalar format and not as a matrix
error=max(abs(electricpotential_analytic-electric_potential))/(max(abs(electricpotential_analytic))) %Determines the error from equation 50 as a scalar value
plot(number_of_points,error) %Plots the error function for every number of points
hold on %Holds the value so that multiple values can be plotted on the same figure
end %Terminates the for loop
error = 1.7594
error = 0.4996
error = 0.2639
error = 0.1606
error = 0.1122
error = 0.0810
error = 0.0625
error = 0.0494
error = 0.0399
error = 0.0331
error = 0.0279
xlabel('N','fontsize', 16) %Labels the x axis
ylabel('Error','fontsize', 16) %Labels the y axis

Accepted Answer

Cris LaPierre
Cris LaPierre on 22 Oct 2021
It looks like you are plotting your data one point at a time. MATLAB does not automatically include a marker in the line format, so when you plot a single point, you cannot see the line.
The fix here is to add a markerstyle to your plot command.
clear, clear all, clc
vacuum_permittivity = 1; %Defines epsilon 0 value = 1
for num = 1:11 %Initialises for loop to the length of number_of_point
number_of_point=11:4:51; %Initialises array of the number of points
number_of_points=number_of_point(num); %Selects the part of the number of points array to use for the conditions below
x_1 = -5; %Defines the minimum x axis value
x_N = 5; %Defines the maximum x axis value
x = transpose(linspace(x_1, x_N, number_of_points)); %Transposes x as a matrix with N number of points
y = x; %Defines the x dimensions to be equal to the y dimensions
h = x(2) - x(1); %Finds the 'h' value as the spacings between the points
[X, Y] = meshgrid(x,y); %Initialises the meshgrid for the
electricpotential_analytic=(X.^2+Y.^2).*exp(-X.^2-Y.^2); %Defines the analytical electric potential
sigma=exp(-X.^2-Y.^2).*(12*X.^2-4*X.^2.*(X.^2+Y.^2)+12*Y.^2-4*Y.^2.*(X.^2+Y.^2)-4); %Defines the analytical charge density
% Define our differential operator for two dimensions as a matrix.
A = (1 / h^2) * (diag(ones(1, number_of_points - 1), 1) + ...
diag(-4 * ones(1, number_of_points), 0) + ...
diag(ones(1, number_of_points - 1), -1));
B = (1 / h^2) * diag(ones(1, number_of_points), 0);
L = kron(diag(ones(1, number_of_points), 0), A) + ...
kron(diag(ones(1, number_of_points - 1), 1), B) + ...
kron(diag(ones(1, number_of_points - 1), -1), B);
sigma = reshape(sigma, number_of_points^2, 1); %Reshapes sigma to have the same dimensions as the electric potential
electricpotential_analytic=reshape(electricpotential_analytic,number_of_points^2,1); %Reshapes the electric potential to have the same dimensions as sigma for a matrix
electric_potential=-inv(L)*sigma; %Uses equation 39 to define Poisson's equation in matrix format. No element wise multiplication is done since are interested in the error in scalar format and not as a matrix
error=max(abs(electricpotential_analytic-electric_potential))/(max(abs(electricpotential_analytic))) %Determines the error from equation 50 as a scalar value
% Add markerstyle -------> vvv
plot(number_of_points,error,'o') %Plots the error function for every number of points
hold on %Holds the value so that multiple values can be plotted on the same figure
end %Terminates the for loop
error = 1.7594
error = 0.4996
error = 0.2639
error = 0.1606
error = 0.1122
error = 0.0810
error = 0.0625
error = 0.0494
error = 0.0399
error = 0.0331
error = 0.0279
xlabel('N','fontsize', 16) %Labels the x axis
ylabel('Error','fontsize', 16) %Labels the y axis
  2 Comments
Stephen
Stephen on 22 Oct 2021
Note that this creates multiple separate line objects, each with just one point (as indicated by the different colors). If you want to plot one line, then you will need to collect the data into one array and plot it after the loop.

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