what does the "oldx =[x(n);oldx(1:256)]" in the following programm do?
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ad lyn
el 28 de Oct. de 2021
Respondida: dpb
el 28 de Oct. de 2021
fid = fopen('bbg1AR20.sig', 'r');
x = fread(fid,'int16')
oldx = zeros(256,1);
for n = 1: 256000
oldx =[x(n);oldx(1:255)];
end
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David Hill
el 28 de Oct. de 2021
for n = 1: 256000
oldx =[x(n);oldx(1:255)];%just reforming the oldx array with x(n) on top and then the next 255 elements of oldx and dropping the last element
end
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dpb
el 28 de Oct. de 2021
It will (very inefficiently) append the first 255 elements of the (NEW and this is key) oldx vector onto the value of the read-in vector x after the Nth element, replacing the entire oldx vector on every pass through the loop. But, it is reversing x as it prepends it in front of the newly created vector each pass.
Whether this is the intent or not is probably debatable, but the above result is simply written as
oldx=[flipud(x);zeros(255,1)];
One might make presumptions of what was really intended, but that's what it does.
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