Character Frequency of String

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Sydney Schapansky
Sydney Schapansky el 5 de Nov. de 2021
Respondida: Sayan el 25 de Nov. de 2022
I'm trying to figure out how to get groups and group counts for a string.
For example, if you input
string = "SunnyDay"
the output would be:
S: 1
U: 1
N: 2
Y: 2
D: 1
A: 1
  3 comentarios
Paul
Paul el 17 de Sept. de 2022
I was quite curious as to how this Question popped up today as if it had been asked on 5 Nov 2021 with no activity since then. Any idea how that happened?
Stephen23
Stephen23 el 17 de Sept. de 2022
"Any idea how that happened?"
Because of Kuchi's comment.

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Respuestas (2)

Paul
Paul el 17 de Sept. de 2022
Using the new dictionary in 2022b and the on-point example from this blog post
str = "SunnyDay";
chr = char(str);
d = dictionary(string.empty,double.empty);
for c = chr
if isKey(d,c) % If this char exists in the dictionary
d(c) = d(c) +1; % Increment the value associated with that char by 1.
else
d(c) = 1; % Initialise a new char in the dictionary with the value set to 1.
end
end
d
d =
dictionary (stringdouble) with 6 entries: "S" ⟼ 1 "u" ⟼ 1 "n" ⟼ 2 "y" ⟼ 2 "D" ⟼ 1 "a" ⟼ 1
I tried making the dictionary key a char, but that resulted in an error.

Sayan
Sayan el 25 de Nov. de 2022
str = "SunnyDay";
chr = char(str);
d = dictionary(string.empty,double.empty);
for c = chr
if isKey(d,c) % If this char exists in the dictionary
d(c) = d(c) +1; % Increment the value associated with that char by 1.
else
d(c) = 1; % Initialise a new char in the dictionary with the value set to 1.
end
end

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